HomeworkLib
Question

Determine the K of a reaction from the E of the cell. Pb^+2(aq) + Mg(s) =...

Determine the K of a reaction from the E of the cell.

Pb^+2(aq) + Mg(s) = Pb(s) + Mg^+2(s) + Mg^+2(s)

I get K=7.34*10^32 but that doesn't seem right.

Thanks!

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)

All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
Determine the K of a reaction from the E of the cell. Pb^+2(aq) + Mg(s) =...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Similar Homework Help Questions

  • Consider the following unbalanced equation. Pb(s) + Mg2+(aq) right --> Mg(s) + Pb2+(aq) (a) What are...

    Consider the following unbalanced equation. Pb(s) + Mg2+(aq) right --> Mg(s) + Pb2+(aq) (a) What are the following standard voltages? Include the sign, changing it as appropriate. Use the standard reduction potentials in the Reference Tables. Enter the number of decimal places allowed by the data in the table. -standard oxidation potential for the oxidation half-cell: ___ V -standard reduction potential for the reduction half-cell: ___ V -potential for the entire cell:___ V (b) Select all that apply for the...

  • Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2:...

    Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...

  • 4. A voltaic cell employs the following redox reaction: 2 Fe3+(aq) + 3 Mg(s) → 2...

    4. A voltaic cell employs the following redox reaction: 2 Fe3+(aq) + 3 Mg(s) → 2 Fe(s) + 3 Mg2+(aq) What is the number of electrons that have been transferred in this redox reaction? 5. Use the following reduction potentials to determine if the reaction in Question 4 represents a voltaic or electrolytic cell and if the reaction is spontaneous or non-spontaneous. Fe3+(aq) + 3 e−(aq) → Fe(s) Eo = −0.036 V Mg2+(aq) + 2 e−(aq) → Mg(s) Eo =...

  • What is the Eºcell, AG', and K for the following reaction? 12(s) + Mg(s) → Mg2+(aq)...

    What is the Eºcell, AG', and K for the following reaction? 12(s) + Mg(s) → Mg2+(aq) +2 1. (aq) You must show your work to get credit. Reduction Half-Reaction E° (V) 12 (s) + 2 e- →21 (aq) +0.535 Mg2+ (aq) + 2 e- Mg(s) -2.37 Which compound is being reduced in the following reaction: H2O2 (aq) + 2 Fe2+ (aq) + 2 H3O+ (aq) → 2 Fe3+ (aq) + 4 H20 (1)

  • Calculate the cell potential for the following reaction: Mg (s) + Ag₂SO₄ (aq) → 2 Ag...

    Calculate the cell potential for the following reaction: Mg (s) + Ag₂SO₄ (aq) → 2 Ag (s) + MgSO₄ (aq) E° (Mg²⁺/Mg) = -2.37 V E° (Ag⁺/Ag) = 0.80 V

  • A voltaic cell is based on two lead half cells: Pb+2(aq) + 2 e- → Pb(s)...

    A voltaic cell is based on two lead half cells: Pb+2(aq) + 2 e- → Pb(s) Eo = -0.13 v One half-cell has [Pb(NO3)2] = 0.25 M and one half-cell has [Pb(NO3)2] = 0.0020 M What is the initial potential produced by the voltaic cell. Express your answer in units of volts with 2 significant digits, but do not include the units on the submitted answer.

  • 6. Consider the following galvanic cell and standard reduction potentials: Ag Pb E° = 0.80 V salt bridge Ag+ (aq) + e →...

    6. Consider the following galvanic cell and standard reduction potentials: Ag Pb E° = 0.80 V salt bridge Ag+ (aq) + e → Ag(s) Pb2+(aq) + 2e → Pb(s) E° = -0.13 V 1 M Ag+ 1 M Pb2+ Which one of the following statements is TRUE? a) The cell on the left containing Ag+(aq) is the anode. b) The initial reading on the voltmeter would be 0.67 V. c) Oxidation occurs in the cell on the right containing Pb²+(aq)....

  • Calculate e cell for the electrochemical cell below, Pb(s) |Pb2+(aq, 1.0 M) || Fe2+(aq, 1.0 M)...

    Calculate e cell for the electrochemical cell below, Pb(s) |Pb2+(aq, 1.0 M) || Fe2+(aq, 1.0 M) | Fe(s) given the following reduction half-reactions. Pb2+(aq) + 2 e– ® Pb(s) E° = –0.126 V Fe2+(aq) + e– ® Fe(s) E° = –0.44 V

  • Suppose the galvanic cell sketched below is powered by the following reaction: Ni(s)+Pb(NO3),(aq) → Ni(NO3)2(aq)+Pb(s) E1...

    Suppose the galvanic cell sketched below is powered by the following reaction: Ni(s)+Pb(NO3),(aq) → Ni(NO3)2(aq)+Pb(s) E1 S1 S2 Write a balanced equation for the half-reaction that happens at the cathode of this cell. Write a balanced equation for the half-reaction that happens at the anode of this cell. Of what substance is E1 made? Of what substance is E2 made? What are the chemical species in solution S1? What are the chemical species in solution S2?

  • 1. Consider the following standard reduction potentials, Pb 2 +(aq) + 2 e- → Pb(s) E°...

    1. Consider the following standard reduction potentials, Pb 2 +(aq) + 2 e- → Pb(s) E° = -0.13 V I2(s) + 2 e- → 2 I-(aq) E° = +0.54 V Under standard conditions, Consider the following standard reduction potentials, Pb 2 +(aq) + 2 e- → Pb(s) E° = -0.13 V I2(s) + 2 e- → 2 I-(aq) E° = +0.54 V Under standard conditions, I2(s) is a stronger oxidizing agent than Pb 2+(aq) and Pb(s) is a stronger reducing...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT