Avery, MacLeod and McCarthy’s experiment first determined that DNA was the “transforming principle” present in the cell extract of a pathogenic strain of bacteria. Describe the experiment and explain how the results demonstrated the presence of a “transforming principle” as well as identifying it as DNA.
Avery-MacLeod-McCarty Experiment
There are two strains of bacteria R- rough
S- smooth.
S are virulent or able to cause disease.
R are avirulent. They are unable to cause disease.
R are unable to cause disease but when injected with heat killed
smooth bacteria, they were able to cause the disease.
Now it is need to be tested that which is the transforming
element.
So, lipids, carbohydrates and proteins all are tested.
They prepared cultures containing the heat-killed S strain of the
bacteria and then removed lipids and carbohydrates from the
solution.
they treated the solutions with different digestive enzymes (DNase, RNase or protease) to destroy the targeted compound.
Finally, they introduced living R strain cells to the culture to see which cultures would develop transformed S strain bacteria
Only in the culture treated with DNase did the S strain bacteria fail to grow (i.e. no DNA = no transformation). This means that DNA was the transforming agent.
This indicated that DNA was the genetic component that was being transferred between cells.

Avery, MacLeod and McCarthy’s experiment first determined that DNA was the “transforming principle” present in the...
D 18) How did Avery, MacLeod, and McCarty demonstrate that Griffith's transforming principle was DNA? A) Injecting live S-strain bacteria alone could not kill a mouse. B) Injecting heat-killed S-strain bacterial alone could not kill a mouse. C) Heat-killed S-strain bacterial transformed live R-strain bacteria into live S-strain bacteria. D) DNase, an enzyme that destroys DNA, eliminated the biological activity of the transforming material. E) RNase, an enzyme that destroys RNA, had no effect on the transforming principle.
Is
my reasoning correct? Will leave rate and comment.
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This is what we did in the experiment .First of all,1 µl of
plasmid DNA was added into the tube which contains competent cells
and the tube was tapped gently to mix DNA and the competent
bacteria. After that it was placed on ice for 30 minutes. Then, the
tube with the competent bacteria and plasmid were transferred to
heating block at 42 °C and the tube was leaved in there exactly 90
seconds. 0.25 ml of LB broth was...
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This is what we did in the experiment .First of all,1 µl of
plasmid DNA was added into the tube which contains competent cells
and the tube was tapped gently to mix DNA and the competent
bacteria. After that it was placed on ice for 30 minutes. Then, the
tube with the competent bacteria and plasmid were transferred to
heating block at 42 °C and the tube was leaved in there exactly 90
seconds. 0.25 ml of LB broth was...