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A 1.389 g sample containing some iron(II) in it was dissolved in 1 M H2SO4, then...

A 1.389 g sample containing some iron(II) in it was dissolved in 1 M H2SO4, then titrated with 0.0292 permanganate until the reaction solution was a pale yellow. 6.8 mL of 7.9 M H3PO4 were added to the reaction solution to form a colorless complex with the Fe3+ reaction product. The titration was finished when the pale pink of excess permanganate was visible in the reaction flask. The initial buret reading was 2.4 mL. The final buret reading was 40.1 mL. Question: What is the mass % iron in the sample?

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Answer #1

To solve this problem use the following steps

1.calculate volume of permanganate used from burette readings.

2.Calculate moles of permanganate used by multiplying it's molarity with volume used.

3.Write balanced equation between iron II and permanganate ion.

4.Use unitary method to determine the moles of iron II reacting with moles of permanganate used(calculated in step 2)

5.convert moles of Fe II into mass by multiplying with its molar mass.

6.Calculate mass % by dividing mass of iron × 100 by mass of sample.

The solution is as follows

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