Question

A uniform bar has two small balls glued to its ends. The bar is 2.00 m...

A uniform bar has two small balls glued to its ends. The bar is 2.00 m long and with mass 2.30 kg , while the balls each have mass 0.500 kg and can be treated as point masses.

1. Find the moment of inertia of this combination about an axis perpendicular to the bar through its center.

2. Find the moment of inertia of this combination about an axis perpendicular to the bar through one of the balls.

3. Find the moment of inertia of this combination about an axis parallel to the bar through both balls.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A uniform bar has two small balls glued to its ends. The bar is 2.00 m...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A 0.100-kg, 59.6-cm-long uniform bar has a small 0.070-kg mass glued to its left end and...

    A 0.100-kg, 59.6-cm-long uniform bar has a small 0.070-kg mass glued to its left end and a small 0.140-kg mass glued to the other end. You want to balance this system horizontally on a fulcrum placed just under its center of gravity.

  • A uniform disk with mass M and radius R is rotating about an axis through its center-of-mass.

    A uniform disk with mass M and radius R is rotating about an axis through its center-of-mass. The axis is perpendicular to the disk. The moment of inertial for the disk with a central axis is I MR2. Two non-rotating smaller disks, each with mass M2 and radius R/4, are glued on the original disk as shown in the figure. (a) Show that the ratio of the moments of inertia is given by  I'/I = 35/16, where I' is the moment...

  • A uniform thin rod of mass M=3.15 kg pivots about an axis through its center and...

    A uniform thin rod of mass M=3.15 kg pivots about an axis through its center and perpendicular to its length. Two small bodies, each of mass m=0.235 kg, are attached to the ends of the rod. What must the length L of the rod be so that the moment of inertia of the three-body system with respect to the described axis is I=0.995 kg·m2 ?

  • A 0.110-kg, 51.8-cm-long uniform bar has a small 0.080-kg mass glued to its left end and...

    A 0.110-kg, 51.8-cm-long uniform bar has a small 0.080-kg mass glued to its left end and a small 0.135-kg mass glued to the other end. You want to balance this system horizontally on a fulcrum placed just under its center of gravity. How far from the left end should the fulcrum be placed?

  • A 0.115-kg, 53.6-cm-long uniform bar has a small 0.045-kg mass glued to its left end and...

    A 0.115-kg, 53.6-cm-long uniform bar has a small 0.045-kg mass glued to its left end and a small 0.150-kg mass glued to the other end. You want to balance this system horizontally on a fulcrum placed just under its center of gravity. How far from the left end should the fulcrum be placed?

  • 2. A very thin, flat, uniform slab has a width (W) of 2.00 m, a height...

    2. A very thin, flat, uniform slab has a width (W) of 2.00 m, a height (H) of 30.0 cm, and a total mass of 16.0 kg. Treating the slab as essentially a sheet of mass- distributed uniformly over its area- do the following (i) Use integration to prove that the slab's center of mass is located at its center point. a. (Reminders: dm - ndA dA can be written here as either Hdx or Wdy What is the value...

  • 2. A very thin, flat, uniform slab has a width (W) of 2.00 m, a height...

    2. A very thin, flat, uniform slab has a width (W) of 2.00 m, a height (H) of 30.0 cm, and a total mass of 16.0 kg. Treating the slab as essentially a sheet of mass- distributed uniformly over its area- do the following (i) Use integration to prove that the slab's center of mass is located at its center point. a. (Reminders: dm - ndA dA can be written here as either Hdx or Wdy What is the value...

  • A uniform rod of mass 2.00 kg and length 2.00 m is capable of rotating about...

    A uniform rod of mass 2.00 kg and length 2.00 m is capable of rotating about and passing through its center and perpendicular to its length. A mass m, m, 2.70 kg is attached to the other end of the red treat the two massess point partides. 5.50 kg is attached to one end and a seconds (a) What is the moment of inertia of the system in kg.my (6) If the rod rotates with an angular speed of 2.60...

  • A very thin, straight, uniform rod has a length of 3.00 m and a total mass...

    A very thin, straight, uniform rod has a length of 3.00 m and a total mass of 7.00 kg. Treating the rod as essentially a line segment of mass (distributed uniformly), do the following: (i) Use integration to prove that the rod's center of mass is located at its center point. (Reminders: dmnds mass (and that axis is perpendicular to the rod). with the previous result-to calculate lemr the moment of inertia of the rod about an axis through one...

  • Constants Part A A 0.170-kg, 52.0-cm-long uniform bar has a small 0.080-kg mass glued to its...

    Constants Part A A 0.170-kg, 52.0-cm-long uniform bar has a small 0.080-kg mass glued to its left end and a small 0.145-kg mass glued to the other end. You want to balance this system horizontally on a fulcrum placed just under its center of gravity How far from the left end should the fulcrum be placed? You may want to review (Pages 340 - 343) For related problemsolving tips and strategies, you may want to view a Video Tutor Solution...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT