When 16 g of methane (CH4; molar mass 16.042 g/mol) and 32 g of oxygen (O2;...
When 16 g of methane (CH4; molar mass 16.042 g/mol) and 32 g of oxygen (O2; molar mass 32.00 g/mol) reacted to produce carbon dioxide and water, 11 g of carbon dioxide was produced. Calculate the % yield of carbon dioxide in this reaction.
a. 5.0%
b. 10%
c. 25%
d. 50%
e. 75%
Homework Answers
CH4 + 2O2 ----------------------> CO2 + 2H2O
16 g 64 g 44 g
16 g 32 g
limiting reagent is O2 .
mass of CO2 produced = 44 x 32 / 64 = 22 g
theoretical yield = 22 g
percent yield = actual x 100 / theroretical
= 11 x 100 / 22
= 50 %
answer : d) 50 %
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