Suppose that ??, ??, … … ??, ??+? are all random variables from a ?or(?, ?^?) distribution. Additionally, suppose that we are able to observe (or measure) realizations of ??, ??, … … ??. Our goal is to use these ? observations to predict ??+?. An equivalent problem statement is that we want to derive a (?− ?a)% confidence interval for the random variable ??+? based on observed values of the first ? realizations of the normal random variable ??. Such an interval is known as the (?-?a)% prediction interval.
(a) Derive this prediction interval. (Hint: Your prediction interval should be based on the sample mean ?? and sample variance, ??^? that you have access to based on the first ? observations. Also, remember that a normal variable divided by a sample standard deviation typically follows a ?(?-?) distribution as we have seen before while deriving confidence intervals).
(b) The number of steps one of my colleagues walked in the last seven days was tracked using a cell phone app to be ?822, ?333, ?420, ?432, ?252, ?005, and ?752. Assuming that conditions remain the same, provide a prediction interval with ?5% confidence that will contain the number of steps walked by this person on the eighth day.
Suppose that ??, ??, … … ??, ??+? are all random variables from a ?or(?, ?^?)...
Let X1, X2, ..., Xn be a random sample from the N(u, 02) distribution. Derive a 100(1-a)% confidence interval for o2 based on the sample variance S2. Leave your answer in terms of chi-squared critical values. (Hint: We will show in class that, for this normal sample, (n − 1)S2/02 ~ x?(n − 1).)
Suppose a random sample of 16 is selected from a population with a normal distribution with a known population standard deviation σ of 10. Assume that the sample mean is 4.2. Based on a 90% confidence interval for the population mean, we can conclude that 0.1 is a plausible number for the population mean μ. True False
Suppose we assume that X1, X2, . . . , Xn is a random sample from a「(1, θ) distribution a) Show that the random variable (2/0) X has a x2 distribution with 2n degrees of freedom. (b) Using the random variable in part (a) as a pivot random variable, find a (1-a) 100% confidence interval for
A random sample of 120 observations produces a mean of 38.2 from a population with a normal distribution and a standard deviation of 3.6. a. find a 90 % confidence interval of ų _____<ų<_______ b fina a 95% confidence interval of ų _____<ų<______
the random sample shown below was selected from a normal distribution 7, 6 , 5 , 6 , 9 , 3 a.) construct a 90% confidence interval for the population. mean U (__,__) b assume that sample mean x and sample standard deviation s remain exactly the same as those just calculated but that are based on a sample of n=25 observations. What is the effect of increasing the sample size in the width of the confidence intervals?
8.40
stion 4 (6 pt) (Ex. 8.40 on page 409 is modified): Suppose that random variable Y is an observation from a normal distribution with unknown mean u and variance l Find and verify a pivotal quantity that you can use to derive confidence limits for the mean u. Find a 95% lower confidence limit for. a. b. 8.40 Suppose that the random variable Yis an observation from a normal distribution with unknown mean μ and variance 1 . Find...
Suppose we were to gather a random sample of 21 observations from a population and wished to calculate a 98% confidence interval for the mean, w, in the case where the population standard deviation, is unknown. Enter the value from the Student's distribution that we would use, to three decimal places
The random sample shown below was selected from a normal distribution. 3,6,8,3,8,8 Complete parts a and b. a. Construct a 99% confidence interval for the population mean μ. (1.971,10.03) (Round to two decimal places as needed.) b. Assume that sample mean x overbar x and sample standard deviation s remain exactly the same as those you just calculated but that are based on a sample of n=25 observations. Repeat part a. What is the effect of increasing the sample size...
The random sample shown below was selected from a normal distribution. 3,6,8,3,8,8 Complete parts a and b. a. Construct a 99% confidence interval for the population mean μ. (1.97,10.03) (Round to two decimal places as needed.)b. Assume that sample mean x overbar x and sample standard deviation s remain exactly the same as those you just calculated but that are based on a sample of n=25 observations. Repeat part a. What is the effect of increasing the sample size on...
10. Based on a random sample of size 7 from a normal distribution with mean y, a confidence interval is constructed for y. The sample standard deviation is calculated as 5.4763. Let to be the critical value of a t random variable with v degrees of freedom. The following table lists values of ta for specific combinations of a and v: v=6 v = 7 a=0.1 a = 0.05 a= 0.025 1.440 1.943 2 .447 1.4151.8952.365 If we want to...