Question

Gallium-67 is used medically in tumor-seeking agents. The half-life of gallium-67 is 78.2 hours. If you begin with 41.1 mg of this isotope, what mass remains after 152 hours have passed? mg=

Answer 1

Given that half-life of Gallium-67 = 78.2 hours

Initial mass of Gallium-67 = 41.1 mg

time required for two half-lifes = 2 x 78.2 = 156.4 hours

Mass of Gallium-67 after two half-lives = 41.1 / 4 = 10.275 mg

for 156.4 hours mass of Gallium-67 will be 10.275 mg

mass after 152 hours =

Final mass of Gallium-67 after 152 hours = 9.9859 mg 9.99 mg

*****Please rate***** thumps up*****