Question

PYTHON

Write a program to enter a valid variable till the user wants to end. The program should display the count of positive, negative, zeros and letters (upper and lower case)/symbols (error handling) entered.

Based on the problem, you need to design an algorithm as follows:

1. Get the user input until “n” is entered

2. Add to the positive if it is greater than zero

3. Add to the negative if it is less than zero

4. Add to the zero if it is neither less than or greater than zero

5. Add to the letters/symbols if it none of the above

6. Output the totals as seen in sample output

Note: You need to prompt the user for input and continue to do so until “n” is selected and produce the specified output! (See below)

§ Hint: Use a Loop

Sample Output

User input: Enter input : 56

Do you want to Continue(y/n)? y

Enter input : -9

Output:

Positive Number(s) : 3

Negative Number(s) : 4

Zero(s) : 2 Letter(s) : 1

Symbol(s): 1

Answer 1

note: keep track of identation if any

#happy learning and don't forget to upvote

python code:

#!/usr/bin/env python
# coding: utf-8

# In[1]:

#create a dictionary to track count initialize the variables count to 0
count_dict={'greater_than_zero':0,'less_than_zero':0,'zero':0,'letter':0}

# In[2]:

#infinite loop
while True:
num =input("Input number or 'n' to quit : ")
if 'n'==num.lower(): #check for n, the breaking condition
break
try:
num=int(num)
if int(num) == 0:
#condition for zero
count_dict['zero']+=1
elif int(num) >0: #condition for positive numbers
count_dict['greater_than_zero']+=1
elif int(num) < 0: #condition for negative
count_dict['less_than_zero']+=1 #increment the counter
else:
continue
except:
count_dict['letter']+=1
continue
count_dict

# In[3]:

print('Positive Number(s) : {}'.format(count_dict['greater_than_zero']))
print('Negative Number(s) : {}'.format(count_dict['less_than_zero']))
print('Zero(s) : {}'.format(count_dict['zero']))
print('Symbol(s) : {}'.format(count_dict['letter']))

# In[ ]: