Question

Given typical operator precedence rules, what would be printed to the console if operands were evaluated...

Given typical operator precedence rules, what would be printed to the console if operands were evaluated from left to right, and all operands had an equivalent precedence level?

int no_se (int n1, int n2)

{

return n1 + n2;

}

int se (int *n1, int * n2)

{

return *n1 += *n2;

}

int main()

{

int x = 2, y = 2;

int result = se(&x,&y) + x + no_se(x,y);

printf(“%d\n”, result);

}

A. 10

B. 16

C. 14

D. 12

0 0
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Answer #1
Output to the console if operands were evaluated from left to right is 14

C. 14
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