Question

A major leaguer hits a baseball so that it leaves the bat at a speed of 33.0 m/s and at an angle of 34.2 ∘ above the horizontal. You can ignore air resistance PART C Calculate the vertical component of the baseball's velocity at an earlier time calculated in part (a). PART D Calculate the horizontal component of the baseball's velocity at a later time calculated in part (a). PART E Calculate the vertical component of the baseball's velocity at a later time calculated in part (a). PART F What is the magnitude of the baseball's velocity when it returns to the level at which it left the bat? PART G What is the direction of the baseball's velocity when it returns to the level at which it left the bat?

Answer 1

c)

vy = 33 sin 34.2 = 18.549 m/s

d)

vx = 33 cos 34.2 = 27.294 m/s

e)

vy' = vy - gt = 27.294 - 9.8* t

note: just put the vlue of time (t) from part (a) to have a numerical vlue for this part or let me know ita value in comments

f)

velocity remains same as projected value = 33 m/s

g)

it is directed at 34.2 below horizontal

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Comment before rate in case any doubt, will reply for sure.. goodluck