A student weighs out 1.269 g of sodium carbonate decahydrate and prepares a solution using a...
A student weighs out 1.269 g of sodium carbonate decahydrate and prepares a solution using a 100 mL volumetric flask. What is the concentration of this stock solution? If the student the uses a 10 mL volumetric pipet to transfer a sample of their stock solution into a 25 mL volumetric flask before diluting the solution to the mark following the correct procedure, what is the concentration of this dilute solution?
Homework Answers
mass of Sodium carbonate decahydrate (Na2CO3.10H20) = 1.269 grams
molar mass of Sodium carbonate decahydrate = 286.14 gram/mol
number of moles of Sodium carbonate decahydrate = mass/molar mass = 1.269 / 286.14 = 0.0044 mol
volume of the solution = 100 mL = 0.100L
Concentration of the solution = number of moles / volume in L = 0.0044;/0.100 = 0.044M
concentration of stock solution = 0.044M
Initial condition Final condition
M1= 0.044M M2=
V1= 10.0mL V2= 25mL
for dilution
M1V1=M2V2
0.044 x 10.0 = M2 x 25.0
M2= 0.0176M
concentration of dilute solution = 0.0176M
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