Debbie displays four dominant traits: naturally curly hair, a widow's peak hairline, unattached earlobes, and freckles....
Debbie displays four dominant traits: naturally curly hair, a widow's peak hairline, unattached earlobes, and freckles. Chuck also displays the same four dominant traits. Assume Debbie and chuck are heterozygous for each gene.
What is the likelihood of any child of Chuck and Debbie:
Has curly hair, a widow's peak hairline, unattached earlobes, and freckles?
Has curly hair, a straight hairline, attached earlobes, and freckles?
Has straight hair, a straight hairline, attached earlobes, and no freckles?
Will be heterozygous for all four traits?
Homework Answers
Answer:
Curly hair= C; Strait hair = c
Widow’s peak = W ; straight hairline = w
Unattached earlobes = E; Attached earlobes = e
Freckles = F; No freckles = f
Cc Ww Ee Ff X Cc Ww Ee Ff -----Parents
Cc x Cc= C_ (curly hair-3/4) & cc (straight hair-1/4)
Ww x Ww = W_ (widow’s peak) & ww (straight hairline-1/4)
Ee x Ee = E_ (unattached earlobes-3/4) & ee (attached earlobes-1/4)
Ff x Ff = F_ (freckles-3/4) & ff (no freckles-1/4)
Has curly hair, a widow's peak hairline, unattached earlobes, and freckles = C_W_E_F_ = 3/4*3/4*3/4*3/4 = 81/256
Has curly hair, a straight hairline, attached earlobes, and freckles = C_wweeF_ = 3/4*1/4*1/4*3/4 = 9/256
Has straight hair, a straight hairline, attached earlobes, and no freckles = ccwweeff = 1/4*1/4*1/4*1/4 = 1/256
Will be heterozygous for all four traits = ½ * ½ * ½ * ½ = 1/16
Add Answer to:
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