The process through which fragments of Deoxyribonucleic acid (DNA) are broken as well as recombined which results in a new allelic combination is regarded as recombination.
Distance between two genes measured in centimorgan (cM) or map unit (mu), which helps in ascertaining the relative distance between two linked genes.
Recombinant frequency can be calculated as,
1 map unit = 1 centi Morgan (cM) = 1% recombination
Given: 16 centi Morgan
To find: percentage of gametes expect to be recombinant that is recombination frequency
1 cM = 1% recombination
Therefore, 16 cM = 16% recombination.
in humans if two genes are 16 centi morgans apart what percent of gametes would you...
5. In humans, if two genes are 28 CM apart on the same chromosome, what percentage of gametes would you expect to be recombinant with respect to these two genes? Show your work. (9 points)
Explain why two genes 50 or more map units apart on a genetic map can only result in a maximum of 50% recombinant gametes in two point cross. To answer this, ask yourself what percentage of recombinant gametes would result if the probability of crossing over in a tetrad involving these genes were 100%, as it would be if the two genes are 50 or more map units apart.
If two genes are 24 cM apart on a genetic linkage map, how many recombinant offspring would you expect out of 150? A. Depends if they are cis or trans B. 18 C. 24 D. 36 E. 12
The B and N genes are 25 map units apart on a chromosome. a) Following a dihybrid testcross, how many offspring of 250 would you expect to display a recombinant phenotype? a) If you performed a dihybrid testcross, with a cis dihybrid, what would be the genotypes of both recombinant offspring phenotypic classes?
If two bacterial genes are 0.5 minutes apart on the bacterial chromosome, what frequency of cotransductants would you expect to observe in a P1 transduction experiment in E.coli (3 points) 3.
Two genes are linked, close together, and heterozygous in an individual. Assume this individual produces a lot (~1000) of gametes. Which would be more common, the recombinant genotype gametes or the parental genotype gametes? Please offer a reason for your answer.
1.
2.
13.
Which statement explains why the recombination frequency between two genes is always less than 50%? Recombination cannot be more than 50% because chromosomes are only 50 map units in length. The genotype of the F, gametes will always be 50% parental gametes and 50% recombinant gametes. Genes with a recombination frequency near 50% are unlinked and have an equal likelihood of being inherited together or separately. F1 gametes always have 50% of their alleles from each parental...
In flamingos, genes A and B are known to be 21 map units apart on chromosome #5. You mate an AA:BB male with an aa:bb female to produce F1 flamingos. a. What gametes will be made by these F1 individuals and in what proportions? b. When the F1's are bred to each other, they produce a total of 276 offspring. How many of these offspring would you predict should have the genotype Aa:BB?
2. Two particular genes are linked and 14 map units apart. A GBIGB individual is mated with a gblgb individual. a) Show the genotype of an FI offspring demonstrating linkage. b) What gametes can the Fl produce AND in what frequency? If the F1 generation mate amongst themselves, what is the frequency of GGbh F2 offspring? (show your work) c)
Pigment of chicken feathers is regulated by two genes, the gene for feather pigment C, and a gene that inhibits pigment production, I. A mother chicken, who is homozygous dominant for gene C, and heterozygous for gene I, is crossed with a father chicken, who is heterozygous for the pigment gene, and heterozygous for gene I. Inhibition is dominant to uninhibited, pigmented feathers are dominant to unpigmented feathers. The inhibitor gene (I) will prevent expression of pigmented chicken feathers. A)...