The vector position of a 3.15 g particle moving in the xy plane varies in time according to r1 = (3î + 3ĵ)t +...
The vector position of a 3.15 g particle
moving in the xy plane varies in time according
to r1 = (3î + 3ĵ)t + 2ĵt2
where t is in seconds and r is in
centimeters. At the same time, the vector position of
a 5.75 g particle varies
as r2 =
3î − 2ît2 − 6ĵt.
(a)Determine the velocity (in cm/s) of the center of
mass at t = 2.80 s.
(b)Determine the acceleration (in cm/s2) of
the center of mass
at t = 2.80 s
(c)Determine the net force (in µN) exerted on the two-particle system at t = 2.80 s.
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