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The vector position of a 3.00 g particle moving in the xy plane varies in time...

The vector position of a 3.00 g particle moving in the xy plane varies in time according to r1 = (3î + 3ĵ)t + 2ĵ(t^2 )where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.75 g particle varies as r2 = 3î − 2ît2 − 6ĵt.

(a). Determine the vector position (in cm) of the center of mass of the system at t = 2.80 s.

(b). Determine the linear momentum (in g · cm/s) of the system at t = 2.80 s.

(c). Determine the velocity (in cm/s) of the center of mass at t = 2.80 s.

(d). Determine the acceleration (in cm/s2) of the center of mass at t = 2.80 s.

(e). Determine the net force (in µN) exerted on the two-particle system at t = 2.80 s.

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