What is the molar mass of 0.85 g of an unknown, non-electrolyte, compound that depresses the freezing point of 100. g of benzene by 0.47°C? Kf of benzene is 5.12ºC/m.
What is the molar mass of 0.85 g of an unknown, non-electrolyte, compound that depresses the...
The molar mass of unknown molecular compound is determined using freezing point depression. The substance is dissolved in benzene (C6H), an organic solvent. Use the data below to determine the molar mass of the substance. 8.65 g Mass of unknown compound Freezing point of solution Volume of benzene -10.21°C 35.0 mL 5.53°C Freezing point of benzene Density of benzene Kf for benzene 0.8765 g/mL 5.12°C/m Molar mass = g/mol
Determine the molar mass of an unknown non-electrolyte compound given the following data: 1.453 grams of the unknown compound is dissolved in 10.08 grams of water (Kf = 1.853 0C/m). The solution freezes at -1.47 0C. What is the molar mass of the unknown compound?
A solution is prepared by dissolving 0.107 g of an unknown non-electrolyte in 88.1 g of camphor. The freezing point of the solution was measured to be 178.0�C. What is the molecular weight of the compound? (The freezing point of pure camphor is 179.5�C and kf= 40�C/m)?
A solution containing 1.00 g of an unknown non-electrolyte liquid and 9.00 g water has a freezing point of -3.33 oC. The Kf = 1.86 oC/m for water. Calculate the molar mass of the unknown liquid, in g/mol.
13. A 0.230 m solution of an unknown electrolyte depresses the freezing point of water by 0.821°C. What is the Van't Hoff factor for this electrolyte? The freezing point depression constant for water is 1.86 °C/m. a. 0.521 b. 1.92 c. 2.00 d. 2.30 e. 4.41
What is the molar mass of a nonpolar molecular compound if 6.34 g dissolved in 53.4 g benzene begins to freeze at 2.81 °C? The freezing point of pure benzene is 5.50 °C and the freezing point depression constant, Kf, is -5.12 °C/m. A. 2.26 x 10-4 g/mol B. 0.226 g/mol C. 12.1 g/mol D. 226 g/mol
A solution made by dissolving 150.0 g of an unknown compound in 425.0 mL of benzene to make a solution which has a freezing point 18.6 °C lower than that of pure benzene. Kf for benzene is 5.12 °C/m and the density of benzene is 0.877 g/mL. b) The molality of the solution is 3.63. How many moles of the unknown compound were dissolved in the solution? C) what is the molar mass of the unknown compound?
Problem # 3: what is the molar mass of 35.0 g of an unknown substance that depresses the freezing point of 0.350 kg of water 0.50 °C? K, for water is 1.86 °C/m. [10 points
When 0.60 grams of a non-electrolyte unknown compound is dissolved in 10 grams of water, the freezing point of the solution is -1.86o C. Given that the freezing point of pure water is 0o C and that the freezing-point depression constant for water is 1.86 o C/mol/kg, calculate the molecular mass (g/mol) of the unknown compound.
When 9.31 g of an unknown non-electrolyte is dissolved in 50.0 g of benzene, the boiling point increased by 3.16 degrees C. If the Kbp of the solvent is 2.53 K/m, calculate the molar mass of the unknown solute. The answer is 149 ± 2% looking for explanation how to work this problem