Consider the combination reaction of vanadium metal and oxygen gas.
If you start with 40.9 moles of vanadium metal, how many
moles of oxygen gas would be
required to react completely with all of the vanadium metal? For
this reaction, vanadium has an oxidation state of +5 in the
product.
The reaction that occurs is:
2 V + 5 + 5/2 O2 = V2O5
We calculate the moles of O2 needed to complete the reaction:
n O2 = 40.9 mol V + 5 * (5/2 mol O2 / 2 mol V + 5) = 51.125 mol O2
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