Minimum energy of photon should be such that the sum of rest mass energy of proton and energy of photon in reactant side must be equal to sum of rest mass energies of proton and neutral pion on product side. However if the difference between reactant and product quantities is positive the reaction is possible and the energy difference is transmitted as kinetic energy in the products.But if this difference is negative then reaction would not be possible. Therefore if minimum energy of photon is E to occur this reaction then,
E + 938 = 938 + 135 MeV,
E = 135 MeV
Threshold for pi meson production* A high energy photon (γ-ray) collides with a proton at rest....
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Show that the threshold kinetic energy in the Laboratory for the production of n pions in the collision of protons with a hydrogen target is given by T= 2nm (1 + nm,/4mp) where m, and mp are respectively the pion and proton masses. A gamma ray interacts with a stationary proton and produces a neutral pion according to the scheme y + p → P +7° Calculate the threshold energy given Mp =...
Gamma rays (γ-rays) are high-energy photons. In a certain nuclear reaction, a γ-ray of energy 0.308 MeV (million electronvolts) is produced. Compute the frequency of such a photon.
Gamma rays (γ-rays) are high-energy photons. In a certain nuclear reaction, a γ-ray of energy 0.505 MeV (million electronvolts) is produced. Compute the frequency of such a photon. answer in Hz?
Gamma rays (γ-rays) are high-energy photons. In a certain nuclear reaction, a γ-ray of energy 0.815 MeV (million electronvolts) is produced. Compute the frequency of such a photon. Answer must be in Hz.
In addition to its rest energy, a moving proton (p') has kinetic energy. This proton collides with a stationary proton (p), and the reaction forms a stationary neutron (n), a stationary proton (p), and a stationary pion (π+), according to the following reaction: p' + p → n + p + π+. The rest energy of each proton is 938.3 MeV, and the rest energy of the neutron is 939.6 MeV. The rest energy of the pion is 139.6 MeV....
The discovery of the antiproton p (a particle with the same rest energy as a proton, 938 MeV, but with the opposite electric charge) took place in 1956 through the following reaction: p + p → p+p+p+¯ p, in which accelerated protons were incident on a target of protons at rest in the laboratory. The minimum incident kinetic energy needed to produce the reaction is called the threshold kinetic energy, for which the final particles move together as if they...
PHYS10121 a) A particle of rest mass m is travelling so that its total energy is 2mc. It collides with a stationary particle of rest mass m to form a new single particle. What is the 2. rest mass of the new particle? 9 marks] b) A photon hits an electron at rest and produces an electron-positron pair according to the reaction γ+ e- e" + e-+e+, what is the smallest possible photon energy for this to occur? You may...
3. (10 pts) High energy particle accelerators convert part of the energy of colliding particles into the masses of particles produced in the collisions. Consider a collision of two protons that produces two charged kaons. The mass of the proton is mp- 938.3 MeV/c2, and the mass of each kaon is mK 493.7 MeV/c2. The reaction is a) The total energy (kinetic energy and rest energy) and total momentum is conserved. Suppose one of the protons is at rest in...