Question

The discovery of the antiproton p (a particle with the same rest energy as a proton, 938 MeV, but with the opposite electric charge) took place in 1956 through the following reaction: p + p → p+p+p+¯ p, in which accelerated protons were incident on a target of protons at rest in the laboratory. The minimum incident kinetic energy needed to produce the reaction is called the threshold kinetic energy, for which the final particles move together as if they were a single unit. Find the threshold kinetic energy to produce antiprotons in this reaction.

Answer 1

final state t particle 1 (proton) is moring while 2 is at rest. For the threshold kinetic energy the final produce will be in a lomp with some velocity Day, the Enery proton proton 1 is carrying is & & the rest mas Energy of s potin – mo and the moment un for 1 in p & momenton for 24 o re So the dous momentum for thre incident particle as this will be equal to find 4momentum Now the way in their will look like an center of mass frame. as the kinetic energy to threshold So it will be actually t o zero relocity. So de Po - (ameo) As each particle So de Pr - (ame, o has nest mass on

Now in: relativity Por is must be equal to So e me)-pt - (Ame) 2 16mm 3 - 4 metr Emas - 16mmer Now that mich 9, P. " , " Em Là y a time 7 + 2 Em - komen I 7 REm = Ilme-amer z lumea a E27me so if the kinetic energy & I time the reaction wit is possible so the threshold enery & 2 Ime 7x938) Mer 2.6566 Mer 626:566 Ger & the threshold energy 6.566 Ger
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