stoichiometry review: you measure 4.0 mL of 2.2 mol/L HCl, and you mix this with 30.5 mL of 3.25 mol.L NaOH. These undergo a neutralization reaction. which reactant is the limiting reactant? What is the theoretical yield of your product? show work for full credit
balanced reaction is needed to find theoretical yield
NaOH + HCl --> naCl + H2O
given
volume of HCl = 4 ml
molarity of Hcl= 2.2 mols/l
mols of HCl present = volume *molarity = 4ml* 2.2 M
= =8.8 milli mols
volume of naOH = 30.5 ml
molarity of NaOH = 3.25 M
mols of NaOH present = 30.5 ml*3.25 = 99.125 milli mols
from balanced equation, mol ratio HCl:NaOH= 1:1
Since mols of HCl is fewer than mols of NaOH ,
Limiting reactant : HCl
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Mols of NaCl produced depends on mols of limiting
reactant.
mol ratio HCl:Nacl = 1:1
That means
mols of NaCl formed= mols of HCl present =8.8 milli mols
mas of NaCl formed = mols of NaCl*molar mass of naCl
=8.8x10^-3 mols* 58.44 g/mol
= 0.5143 Grams
Thus
Theoretical yield of NaCl = 0.5143 g
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Thank you
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