Question

The emissivity of the human skin is 97.0 percent. Use 35.0 °C for the skin temperature and approximate the human body by a rectangular block with a height of 1.83 m, a width of 43.0 cm and a length of 30.0 cm.
Calculate the power emitted by the human body.

Tries 0/20

Fortunately our environment radiates too. The human body absorbs this radiation with an absorbance of 97.0 percent, so we don't lose our internal energy so quickly. How much power do we absorb when we are in a room where the temperature is 24.0 °C?

Tries 0/20

How much energy does our body lose in one second?

Answer 1

a] According to Stephan Boltzmann law,

power emitted = e*area*sigma*T^4 where e is emissivity and sigma is Boltzmann constant

= 0.97*[1.83*0.43+1.83*0.30+0.30*1.83]*5.67e-8*(273+35)^4

= 932.9 W answer

b] power absorbed = e*area*sigma*T^4 where e is emissivity and sigma is Boltzmann constant

= 0.97*[1.83*0.43+1.83*0.30+0.30*1.83]*5.67e-8*(273+24)^4

= 806.6 W answer

c] Energy lost per sec = 932.9 - 806.6 = 126.3 J