Calculate the value of ΔH for the reaction: Fe2O3(s)+ 6HCl(g) → 2FeCl3(s) + 3H2O(g)
( ) 164.3 kJ
( ) 88.2 kJ
( ) -24.3 kJ
( ) -146.4 kJ
Calculate the value of ΔH for the reaction: Fe2O3(s)+ 6HCl(g) → 2FeCl3(s) + 3H2O(g) ( )...
Using the following thermochemical data, calculate ΔHf° of Lu2O3(s). 2LuCl3(s) + 3H2O(l) → Lu2O3(s) + 6HCl(g) ΔH° = 316.6 kJ/mol 2Lu(s) + 3Cl2(g) → 2LuCl3(s) ΔH° = -1891.2 kJ/mol 4HCl(g) + O2(g) → 2Cl2(g) + 2H2O(l) ΔH° = -202.4 kJ/mol
Calculate ΔHrxn for the following reaction: Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) Use the following reactions and given ΔH′s. 2Fe(s)+3/2O2(g)→Fe2O3(s), ΔH = -824.2 kJ CO(g)+1/2O2(g)→CO2(g), ΔH = -282.7 kJ
Calculate ΔHrxn for the following reaction: Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) Use the following reactions and given ΔH′s. 2Fe(s)+3/2O2(g)→Fe2O3(s), ΔH = -824.2 kJ CO(g)+1/2O2(g)→CO2(g), ΔH = -282.7 kJ
In the reaction 2Fe(s) + 6HCl(aq) --> 2FeCl3(aq) + 3H2(g), ______ is reduced to _______ and ________ is oxidized to _____.
1.) or the reaction Fe2O3(s) + 3H2(g)2Fe(s) + 3H2O(g) H° = 98.8 kJ and S° = 142.5 J/K The equilibrium constant for this reaction at 348.0 K is 2.) For the reaction C2H4(g) + H2O(g)CH3CH2OH(g) H° = -45.6 kJ and S° = -125.7 J/K The equilibrium constant for this reaction at 275.0 K is looking for the equilibrium constants
11.
For the reaction Fe2O3(s) + 3H2(g) +2Fe(s) + 3H2O(g) AH° = 98.8 kJ and AS° = 142.5 J/K The equilibrium constant for this reaction at 345.0 K is Assume that AHⓇ and AS are independent of temperature. For the reaction 2502(g) + O2(g) +2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K The equilibrium constant for this reaction at 272.0 K is Assume that AH° and AS are independent of temperature.
You are given the following thermodynamic data. 2 Fe(s) + 3/2 O2(g) → Fe2O3(s) ΔH° = -823 kJ 3 Fe(s) + 2 O2(g) → Fe3O4(s) ΔH° = -1120. kJ Calculate the ΔH° for the following reaction. 3 Fe2O3(s) → 2 Fe3O4(s) + ½ O2(g)
Calculate the enthalpy of the reaction 4B(s)+3O2(g)→2B2O3(s) given the following pertinent information: B2O3(s)+3H2O(g)→3O2(g)+B2H6(g), ΔH∘A=+2035 kJ 2B(s)+3H2(g)→B2H6(g), ΔH∘B=+36 kJ H2(g)+12O2(g)→H2O(l), ΔH∘C=−285 kJ H2O(l)→H2O(g), ΔH∘D=+44 kJ
problem 5.72 please assist with parts a,b,c and d. Using values from Appendix C or the internet calculate the value of ΔH∘ for each of the following reactions. a. 4HBr(g)+O2(g)→2H2O(l)+2Br2(l) express answer using five sig figs ΔH∘rxn =...............kJ b. 2NaOH(s)+SO3(g)→Na2SO4(s)+H2O(g)2NaOH(s)+SO3(g)→Na2SO4(s)+H2O(g) (ΔHf∘ Na2SO4Na2SO4 = -1387.1 kJ/molkJ/mol) ΔH∘rxn =...........kJ answer using four sig figs c. CH4(g)+4Cl2(g)→CCl4(l)+4HCl(g) ΔH∘rxn..............kJ express answer in four sig figs d. Fe2O3(s)+6HCl(g)→2FeCl3(s)+3H2O(g) ΔH∘rxn..............kJ express answer in two sig figs
please help with these
Fe2O3(s) + 3H2(g) +2Fe(s) + 3H2O(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.37 moles of Fe2O3() react at standard conditions. AS system JK 2CO(g) + O2(g) +2CO2(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.54 moles of CO(g) react at standard conditions. AS system JK 2NH3(g) + 3N20(g)— 4N2(g) + 3H2O(g) AH = -879.5 kJ and AS° = 288.1 J/K The...