Using the following thermochemical data, calculate
ΔHf° of
Lu2O3(s).
| 2LuCl3(s) + 3H2O(l) → Lu2O3(s) + 6HCl(g) | ΔH° = 316.6 kJ/mol |
| 2Lu(s) + 3Cl2(g) → 2LuCl3(s) | ΔH° = -1891.2 kJ/mol |
| 4HCl(g) + O2(g) → 2Cl2(g) + 2H2O(l) | ΔH° = -202.4 kJ/mol |
Using the following thermochemical data, calculate ΔHf° of Lu2O3(s). 2LuCl3(s) + 3H2O(l) → Lu2O3(s) + 6HCl(g)...
problem 5.72 please assist with parts a,b,c and d. Using values from Appendix C or the internet calculate the value of ΔH∘ for each of the following reactions. a. 4HBr(g)+O2(g)→2H2O(l)+2Br2(l) express answer using five sig figs ΔH∘rxn =...............kJ b. 2NaOH(s)+SO3(g)→Na2SO4(s)+H2O(g)2NaOH(s)+SO3(g)→Na2SO4(s)+H2O(g) (ΔHf∘ Na2SO4Na2SO4 = -1387.1 kJ/molkJ/mol) ΔH∘rxn =...........kJ answer using four sig figs c. CH4(g)+4Cl2(g)→CCl4(l)+4HCl(g) ΔH∘rxn..............kJ express answer in four sig figs d. Fe2O3(s)+6HCl(g)→2FeCl3(s)+3H2O(g) ΔH∘rxn..............kJ express answer in two sig figs
Calculate the value of ΔH for the reaction: Fe2O3(s)+ 6HCl(g) → 2FeCl3(s) + 3H2O(g) ( ) 164.3 kJ ( ) 88.2 kJ ( ) -24.3 kJ ( ) -146.4 kJ
Using the following thermochemical data: 2Y(s) + 6HF(g) → 2YF3(s) + 3H2(g) 2Y(s) + 6HCl(g) 2YC13(s) + 3H2(g) calculate AHⓇ for the following reaction: YF3(s) + 3HCl(g) → YC13(s) + 3HF(g) AH° = -1811.0 kJ/mol AH = -1446.2 kJ/mol Select one: O a. 364.8 kJ/mol O b.-3257.2 kJ/mol C. 182.4 kJ/mol O d.-1628.6 kJ/mol O e. 729.6 kJ/mol
Calculate the heart of formation for aluminum chloride using the following thermochemical equations: 2Al (s) + 6HCl (aq) ---> 2AlCl3 (aq) + 3H2 (g) . ΔH = -1049 kJ HCl (g) ---> HCl (aq) . ΔH = -74.8 kJ H2 (g) + Cl2 (g) ---> 2HCl (g) ΔH = -1845 kJ AlCl3 (s) ---> AlCl3 (aq) ΔH = -323 kJ
Time Remaining Time Remainine 2 points Using the following thermochemical data: 2Cr(s) + 6HF(g) → 2C1F3(s) + 3H2(g) 2Cr(s) + 6HCl(g) → 2CrCl3(s) + 3H2(g) AH"=691.4 kJ/mol Ayº = -559.2 kJ/mol calculate Air for the following reaction: CrF3(s) + 3HCl(g) → CrCl3(s) + 3HF(g) 0 -1250.6 kJ/mol 264.4 kJ/mol 66.1 kJ/mol 132.2 kJ/mol 0 -625.3 kJ/mol Previous
Use the following data to calculate the standard enthalpy of formation of heptane, C7H16 (l). C7H16 (l) + 11 O2 (g → 7 CO2 (g) + 8 H2O (l) ΔH° = -4817 kJ/mol ΔHf° of CO2 (g) = -393.5 kJ/mol ΔHf° of H2O (l) = -285.8 kJ/mol A)-218.2 kJ/mol B)-468.1 kJ/mol C)-223.9 kJ/mol D)-447.8 kJ/mol E)-111.5 kJ/mol
Calculate ΔH for the following reaction, CaO(s) + CO2(g) → CaCO3(s) given the thermochemical equations below. 2 Ca(s) + O2(g) → 2 CaO(s) ΔH = -1270.2 kJ C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ 2 Ca(s) + 2 C(s) + 3 O2(g) → 2 CaCO3(s) ΔH = -2413.8 kJ A compound contains C, H and O as the elements. A 20.0 g-sample is comprised of 1.34 g H and also 8.00 g of C. What...
Consider the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) Using the standard thermodynamic data in the tables linked above, calculate G for this reaction at 298.15K if the pressure of each gas is 12.47 mm Hg. 2. Use standard reduction potentials to calculate the equilibrium constant for the reaction: Ni2+(aq) + 2Cu+(aq)Ni(s) + 2Cu2+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant: G° for this reaction would be...
Consider the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.84 moles of HCl(g) react at standard conditions. S°surroundings = J/K
Consider the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g), calculate G for this reaction at 298.15K if the pressure of each gas is 13.29 mm Hg. ANSWER: kJ/mol