Question

C++

Write a function called reverseArray(char[] , int) that accepts in an array of chars and the size of the array.as parameters. The function should then create a new array that is the same size as the original array. The function should copy the elements from the first array into the second array in reverse order.

So if the initial array is {'a' , 'b', 'c'} then the new array will be {'c', 'b', 'a'}

Then in your main(), create an array of at least size 10, and fill it with char's. Run the array through your function created above and print out both arrays to demonstrate that the reverse method worked.  

Make sure to delete the new array before closing your program.

Answer 1

#include <iostream>
using namespace std;

void printArray(char *arr, int size) {
    for (int i = 0; i < size; ++i) {
        cout << arr[i] << " ";
    }
    cout << endl;
}

char *reverseArray(char *arr, int size) {
    char *copy = new char[size];
    for (int i = 0; i < size; ++i) {
        copy[i] = arr[size-i-1];
    }
    return copy;
}

int main() {
    int size = 10;
    char values[10];
    cout << "Enter 10 characters: ";
    for (int i = 0; i < size; ++i) {
        cin >> values[i];
    }
    cout << "Original Array is: ";
    printArray(values, size);
    char *rev = reverseArray(values, size);
    cout << "Reversed array is: ";
    printArray(rev, size);

    delete[] rev;
    return 0;
}