A 2.0 L vessel is filled with 7.3x10^-4 moles of hydrogen and 6.8x10^-4 moles of oxygen. How much water can be produced ?
We will use the concept of limiting reagant. Here Oxygen is having less no of moles so it will govern the equation and 6.8x10^-4 moles of water will be formed.
Amount of water = moles* molecular mass
= 6.8x10^-4*18= 0.01224 gram of water
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