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If during the standardization of NaOH(aq), the solution was over titrated into a deep color (rather...

If during the standardization of NaOH(aq), the solution was over titrated into a deep color (rather than faint), how would this affect the calculation of the concentration of NaOH?

Check the box for each statement if valid:

The calculated number of moles will be higher

The calculated number of moles will be lower

The calculated number of moles will be the same

The calculated volume of NaOH will be higher

The calculated volume of NaOH will be lower

The calculated concentration of NaOH will be higher

The calculated concentration of NaOH will be lower

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Answer #1

when solution was over titrated into a deep color then more volume of titrant is required.

That indicates there are more concentrated solution of NaOH.

we know,

mole = volume of NaOH solution in L * molarity

as molarity of NaOH obtained more in compare to original molarity in NaOH solution.

so

mole of NaOH is higher than original moles of NaOH.

answer:

The calculated number of moles will be higher

The calculated concentration of NaOH will be higher

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