Plot the resulting convolution
y(t) = -3 rect(t/2) ∗ 5 rect(t + 4) and find y(-4)
Plot the resulting convolution y(t) = -3 rect(t/2) ∗ 5 rect(t + 4) and find y(-4)
3-6. Plot the waveform of y(t) = 4 rect((t + 1)/4) * 2 rect((t - 4)/2). 3-7. Plot the waveform of r(t) = rect((t + 3)/3) * 6 rect(t/3). Problem 3-6: -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 vt) vs. Problem 3-7: -6 -5 - -3 -2 2 3 4 5 6 7 -1 0 ott) vs.
Find the convolution of the following two signals: X(t) ylt). Plot the resulting signal. 1. 0 x (t) y (t)
Using the convolution property of Fourier Transform to find the following convolution: sinc (t) * sinc (4t): [Hint: sinc (t) ön rect(w/2)] sinc(t)sinc(2t) 8 TT 2 sinc(t) п sinc (2t) п sinc (4t) 4
Using the convolution property of Fourier Transform to find the following convolution: sinc (t) * sinc(41) [Hint: sinc(t) TE rect(w/2)) 77 4 sinc (41) 71 sinc(2) TT sinc(t) RICO sinc(t)sinc(20)
Find the Convolution integral y(t)
Please give answers in written detail.
Thanks
Problem 4: Find the convolution integra l y(t) x(t) 1 0 h(t) 1.5 -2 1 0 0.5 1 2
2(a). Compute and plot the convolution of ytryh)x where h(t) t)-u(t-4), x(t)u(t)-u(t-1) and zero else b). Compute and plot the convolution y(n) h(n)*x (n) where h(n)-1, for 0Sns4, x(n) 1, n 0, 1 and zero else.
Problem 05.008-Properties of the convolution of two rect functions. 4 points what are the maximum and minimum values of y for all time? The maximum value of y is and the minimum value is eBook Hint
Fourier transforms using Properties and Table 1·2(t) = tri(t), find X(w) w rect(w/uo), find x(t) 2. X(w) 3, x(w) = cos(w) rect(w/π), find 2(t) X(w)=2n rect(w), find 2(t) 4. 5, x(w)=u(w), find x(t) Reference Tables Constraints rect(t) δ(t) sinc(u/(2m)) elunt cos(wot) sin(wot) u(t) e-ofu(t) e-afu(t) e-at sin(wot)u(t) e-at cos(wot)u(t) Re(a) >0 Re(a) >0 and n EN n+1 n!/(a + ju) sinc(t/(2m) IIITo (t) -t2/2 2π rect(w) with 40 2r/T) 2Te x(u) = F {r) (u) aXi(u) +X2() with a E...
8) Convolution Integral (7 points). Given the following signals x(t) and h(t), compute and plot the convolution y(t) = x(t) *h(t). x(t) = u(t+2) - u(t – 4) h(t) = 5u(t)e-2t
2. (30 marks] Consider the system shown in Fig. 1. Find the output y(t) for the following h(t) and r(t) using the convolution integral. x(r) y(r) h(t) Figure 1: System for Q2 1.5 2t33 0 otherwise h(t)=2rect(-3.5) x(t) = h(t) = 2 rect (-3 -