Question

Arrange the 0.10 M solutions of the following compounds in order of decreasing acidity (most acidic first). No partial credit.

I. CH₃NH₃Br

II. KC₂H₃O₂

III. Ca(C₂H₃O₂)₂

IV. CH₃COOH

V. CCl₃COOH

VI. NaOH

Answer 1

CH3NH3BR is a acidic salt

KC₂H₃O_{2 is a basic salt}

Ca(C₂H₃O₂)_{2 is a basic salt}

CH₃COOH is acid

V. CCl₃COOH is acid

VI. NaOH is strong base

among CH₃COOH and CCl₃COOH, CCl₃COOH is more acidic due to presence os strong electron withdrawing ccl3 group.

ph of basic salt is calculated as

as in Ca(C₂H₃O₂)₂ 2 moles of accetate ionsa are there. Therefore, concentration will be high and ph will be low

therefore the oder is

CCl₃COOH > CH₃COOH > CH3NH3BR > Ca(C₂H₃O₂)_{2 >} KC₂H₃O_{2 >}

NaOH