C PROGRAM HELP
create a new file
calc.c which implements a simple calculator. The calculator
will perform the four basic arithmetic operations
+,
-,
* and
/. The program should prompt the user for the operation to
perform in an endless loop. For example:
calc > 3 + 6
9
calc >
You must implement the calculator such that there is one
calc function which takes as arguments the numerical values
of the two operands and a pointer to the specified function
(add
for
+, etc), plugs the two values into the referenced function,
and returns the result.
Your program should work independent of spaces in the input. For
instance, both
1+2 and
1 + 2 should work. This is actually very easy to do with
scanf, check out its manual page!
If you have any doubts, please give me comment...
#include<stdio.h>
int calc(int n1, int n2, int (*fun)(int, int));
int add(int n1, int n2);
int subtract(int n1, int n2);
int multiply(int n1, int n2);
int division(int n1, int n2);
int main(){
int n1, n2;
char op;
int result;
while(1){
printf("calc > ");
scanf("%d %c %d", &n1, &op, &n2);
switch(op){
case '+':
printf("%d", calc(n1, n2, add));
break;
case '-':
printf("%d", calc(n1, n2, subtract));
break;
case '*':
printf("%d", calc(n1, n2, multiply));
break;
case '/':
printf("%d", calc(n1, n2, division));
break;
default:
printf("Invalid operation");
}
printf("\n");
}
return 0;
}
int calc(int n1, int n2, int (*fun)(int, int)){
return (*fun)(n1, n2);
}
int add(int n1, int n2){
return n1+n2;
}
int subtract(int n1, int n2){
return n1-n2;
}
int multiply(int n1, int n2){
return n1*n2;
}
int division(int n1, int n2){
return n1/n2;
}

C PROGRAM HELP create a new file calc.c which implements a simple calculator. The calculator will...
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