Consider an electromagnet capable of producing a maximum magnetic field of (2.50+1) T. A circular loop...
Consider an electromagnet capable of producing a maximum magnetic field of (2.50+1) T. A circular loop of wire with a diameter of (4.50+8) cm is placed between the poles of the electromagnet. What is the induced EMF in the loop, if the electromagnet is turned on to full strength in (1.20+14) milli-seconds? Assume the loop is perpendicular to the magnetic field. Calculate the answer in volts (V) and rounded to three significant figures.
Homework Answers
magnetic field B =3.50 T
diameter D =12.50 cm
radius (r) =D/2 =6.25 cm
time taken (t) =15.2 ms
From faradays law
induced emf =N*A*dB/dt
induced emf =(1)*pi*(0.0625 m)^2*(3.50 T)/(0.0152 s)
induced emf =2.825754083 V = 2.830 V
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