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1.) a bucket of mass 5 kg is suspended by rope that is wrapped around a...

1.) a bucket of mass 5 kg is suspended by rope that is wrapped around a pulley of twice the mass which is attached to the ceiling. when the system is released from rest the bucket descends with an acceleration of 1m/s^2 . what is the frictional torque in the pulley? assume the pulley to be solid cylinder.

( CAN YOU PLEASE SOLVE THE PROBLEM AS DETAILED AS POSSIBLE PLEASE. THANK YOU IN ADVANCE )

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Answer #1

mg - T = ma

a = 1 m/s^2

m = 5 kg

g = 10 m/s^2

T = 5 ×9 = 45 N

(T-f)r = Ia/r

I = moment of inertia of pulley = 0.5(2m)r^2

So f = 45 - 5 = 40 N

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