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A 0.390 kg particle moves in an xy plane according to x(t) = - 12.0 +...

A 0.390 kg particle moves in an xy plane according to x(t) = - 12.0 + 1.00 t - 3.00 t3 and y(t) = 25.0 + 4.00 t - 9.00 t2, with x and y in meters and t in seconds. At t = 0.700 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?

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