A 0.390 kg particle moves in an xy plane according to x(t) = - 12.0 + 1.00 t - 3.00 t3 and y(t) = 25.0 + 4.00 t - 9.00 t2, with x and y in meters and t in seconds. At t = 0.700 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
A 0.390 kg particle moves in an xy plane according to x(t) = - 12.0 +...
A 0.25 kg particle moves in an xy plane according to x(t) = -15 + 2t - 4t3 and y(t) = 25 + 7t - 9t2, with x and y in meters and t in seconds. Find formulas at time t<35 sec for the (a) the magnitude and (b) the angle (relative to the positive direction of the x axis) of the net force on the particle (in radians), as well as (c) the angle of the particle's direction of...
The position T of a particle moving in an xy plane is given by (3.006.00(3.00 1.00r with in meters and t in seconds. In unit-vector notation, calculate (a) r, (b) v, and (c) a fort 3.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t- 3.00 s? Give your answer in the range of (-180°; 180°) (a) Number (b) Number (c) Number (d) Number j...
The position r of a particle moving in an xy plane is given by r = (4.00t^3 - 4.00t) i + (4.00 - 1.00t^4) j with r in meters and t in seconds. In unit-vector notation, calculate (a) r, (b) V, and (c) a for t = 2.00 s, (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 2.00 s? Give your answer in the...
The position ModifyingAbove r With right-arrow of a particle moving in an xy plane is given by ModifyingAbove r With right-arrow equals left-parenthesis 3.00 t cubed minus 4.00 t right-parenthesis ModifyingAbove i With caret plus left-parenthesis 5.00 minus 1.00 t Superscript 4 Baseline right-parenthesis ModifyingAbove j With caret with ModifyingAbove r With right-arrow in meters and t in seconds. In unit-vector notation, calculate (a)ModifyingAbove r With right-arrow, (b)v Overscript right-arrow EndScripts, and (c)a Overscript right-arrow EndScripts for t = 3.00...
A 0.200 kg particle moves along an x axis according to particle at t-3.30s?Give an expression for the (a) x, (b) y and (c) z components. 140 + 2 O t + 2.00 t2 400 t3 with x in meters and tin seconds ln unit-vector notation, what is the net force acting on the (a) Number Units (b) Number Units (c) Number Units
(1 point) A body of mass 10 kg moves in the xy-plane in a counterclockwise circular path of radius 3 meters centered at the origin, making one revolution every 11 seconds. At the time t 0, the body is at the rightmost point of the circle. A. Compute the centripetal force acting on the body at time t. B. Compute the magnitude of that force. HINT. Start with finding the angular velocity o [rad/s] of the body (the rate of...
The position ModifyingAbove r With right-arrow of a particle
moving in an xy plane is given by ModifyingAbove r With right-arrow
equals left-parenthesis 4 t cubed minus 3 t right-parenthesis
ModifyingAbove i With caret plus left-parenthesis 6 minus 2 t
Superscript 4 Baseline right-parenthesis ModifyingAbove j With
caret with ModifyingAbove r With right-arrow in meters and t in
seconds.
In unit-vector notation, calculate
(a)ModifyingAbove r With right-arrow,
(b)v Overscript right-arrow EndScripts, and
(c)a Overscript right-arrow EndScripts for t = 2...
A particle moves in two dimensions. The x-position in meters of a particle as a function of time in seconds is given by x(t) = 3 - 7t + 4t2. The y-position in meters of the same particle as a function of time in seconds is given by y(t) = 1 + 2t +3t2. If the particle's mass is 3.4kg, what force (magnitude and direction) is being applied?
A particle whose mass is 2.0 kg moves in the xy plane with a
constant speed of 3.0 m/s along the direction.
What is its angular momentum (in kg/m 2 /s) relative to the point
(0, 5.0) meters?
The position vector of a point which moves in the x-y plane is given by: r = (- 0.2 t4 + 1.8 t3 + 1.1 t2) i + (- 0.4 t4 - 1.2 t) j where r is in meters and t is in seconds. Determine the angle between the velocity v and the acceleration a when t = 1.7 sec.