Question

Write a script called “faracha” that plots a vs. b as defined in the following equations:

         a = sin(t)[e^cos(t) – 2cos(4t) – (sin(t/12)⁵)]

         b = cos(t)[ e^cos(t) – 2cos(4t) – (sin(t/12)⁵)]

Where t = [-10;10]. Use 0.01 interval for t. Use 0.01 intervals for t.

Answer 1

import math
import numpy as np
time = np.arange(-10, 10, 0.01) #this creates a numpy array time having elements between -10 to 10 in the interval of 0.1
# like -10, -9.99, -9.98,.......,0,.......9.98, 9.99, 10
a = []
b = []
for t in time:
a.append(math.sin(t) * (math.exp(1)*math.cos(t) - 2*math.cos(4*t) - (math.sin(5*t/12)))) #it creates a list of x elements
b.append(math.cos(t) * (math.exp(1)*math.cos(t) - 2*math.cos(4*t) - (math.sin(5*t/12)))) #it creates a list of y elements

import matplotlib.pyplot as plt #module for plotting graph
x = a
y = b
print(plt.plot(x,y)) #plots the graph

#####

output:

[<matplotlib.lines.Line2D object at 0x0000013401D9C2B0>]

the above functions creates flower like structures