Question

Time of five rotations= 5 seconds

Time of one rotation =1 second

Distance from the shoulder to the elbow = 13.5 inches

Distance from the shoulder to the middle of the hand= 13.3 inches

5. A. What was the average angular acceleration (degrees/s2 and rad/s2) of the hand? How do you know?

B. What was the average centripetal acceleration (m/s2) of the hand? (Hint: remember, it is going in a circle and acp = v2/r.)

6.Complete your answers in the box below regarding these questions about the displacement and angular displacement of the elbow

         A. How far (degrees and rad) did the elbow travel during the five rotations?

         B. How far (m) did the elbow travel during the five rotations?

         C. How do these compare to the hand? Why are they the same and/or different?

         D. What was the average angular speed (degrees/s and rad/s) of the elbow?

         E. What was the average linear speed (m/s) of the elbow?

         F. How do these compare to the hand? Why are they the same and/or different?

7. Complete your answers in the box below regarding these questions about the acceleration and angular acceleration of the elbow

         A. What was the average angular acceleration (degrees/s2 and rad/s2) of the elbow?

         B. What was the average centripetal acceleration (m/s2) of the elbow?

         C. How do these compare to the hand? Why are they the same and/or different?

Answer 1

(5)
(A) Since every rotation is taking equal time, therefore angular acceleration would be zero.
(B)
Distance of the hand from the shoulder (R) = 13.3 inches = 0.338 m
Now the angular velocity of the rotation would be

Therefore the centripetal acceleration would be

(6)
(A)
Angular displacement in one rotation = 2
Therefore in 5 rotation, angular displacement would be

Now we know that

Therefore angular displacement in 5 rotation would be

(B)
Distance of elbow (r) =13.5 inches = 0.343 m
Therefore,

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