Question

(do in Java ) The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum

Answer 1

public class TestCode {
    public static void main(String args[]){
        int n = 100;
        int sum1 = 0;
        for(int i = 1;i<=n;i++){
            sum1 += (i*i);
        }

        int sum2 = 0;
        for(int i = 1;i<=n;i++){
            sum2 += i;
        }
        sum2 = sum2 * sum2;

        System.out.println(sum2-sum1);
    }
}

25164150