CCl4(g) <---> C(s) + 2 Cl2 (g) , Kp=0.86 If 2.50 atm of CCL4 is added...

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CCl₄(g) <---> C(s) + 2 Cl₂ (g) , Kp=0.86

If 2.50 atm of CCL₄ is added to a flask and allowed to reach equilibrium. What are the final pressures of CCl₄ and Cl₂ at equilbrium?

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