1. what is the [H+] if the [OH-]=7.1x10^-8? 2. what is the pH of a solution...

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Question

1. what is the [H+] if the [OH-]=7.1x10^-8?

2. what is the pH of a solution with [OH-]=2.1x10^-4?

3. what is the [H+] if the pH=3.17?

4. what is the [OH-] if the pH=7.20?

science chemistry

Answer 1

Answer #1

1) we know poh = -log[OH^-] substitiute value we get poh = -log(7.1x10^-8) = 7.14

ph = 14 - poh = 14- 7.14 = 6.86

we know formula [H⁺] = 10^-ph = 10^-6.86 =1.38 x 10^-7

ans [H⁺] = 1.38 x 10^-7 M

2) we know formula poh = -log[OH^-] = -log(2.1x10^-4) = 3.6

pH = 14 - pOH = 14-3.6 = 10.4

ans PH = 10.6

3) we know formula [H⁺] = 10^-PH substitute value [H⁺] = 10^-3.17 = 6.76x10^-4

ans [H⁺] = 6.76x10^-4 M

4) we know formula P^OH = 14 - P^H = 14-7.2 = 6.8

we know formula [OH^-] = 10^-POH substitute value [OH] = 10^-6.8 = 1.58x10^-7

ans [OH^-] = 1.58x10^-7M

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Answer 2

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