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(c19p12) A slender, 300- g bar magnet 25.0 cm long has a magnetic moment of 5.90...

(c19p12) A slender, 300- g bar magnet 25.0 cm long has a magnetic moment of 5.90 A m2. It is held at an angle of 45 o to the direction of a uniform magnetic field. When released, it begins to rotate about its center with an initial angular acceleration of 5.87×102 rad/s2. What is the magnitude of the magnetic field?

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Answer #1

Torque, T = u B sin(theta)

T = 5.90 x B sin(45) = 4.17 B

T = I a

4.17 B = (0.3 x 0.25^2/12) x 587

Magnetic field, B = 0.22 T

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