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A 0.0270-kg BB traveling at 200.0 m/s east hits a motionless 3.30-kg block and bounces off...

A 0.0270-kg BB traveling at 200.0 m/s east hits a motionless 3.30-kg block and bounces off it, retracing its original path with a velocity of 100.0 m/s west. What is the final velocity of the block? Assume the block rests on a frictionless horizontal surface. If the final velocity of the block is toward east, enter a positive value and if the final velocity of the block is toward west, enter a negative value. m/s

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Answer #1

Given :

Mass , m = 0.0270 kg

v = 200 m/s

Mass, M = 3.30 kg

v' = - 100 m/s

To calculate : The final velocity of the block.

We assume that the block rests on a frictionless horizontal surface.

From the law of conservation of linear momentum

Therefore the final velocity of the block is 2.45 m/s

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