2. You observed the ages of a random sample of 8 men in a bar. The average age was 42. It is known that the ages are normally distributed with a standard deviation of 10.
(a) Find a 95% confidence interval for the average age of men in that bar.
(b) Will the 95% confidence interval include approximately 95% of the ages of men in that bar? Explain why or why not.
(c) How many men need to be observed in order for the margin of error of the 95% confidence interval to be at most $5 years?
2. You observed the ages of a random sample of 8 men in a bar. The...
a.) The margin of error in a 95% confidence interval for the true mean of a population is 2.5, based on a random sample of 100 measurements. If the sample mean is 27.5, the 95% confidence interval must be b.) In a random sample of 100 measurements from a population with known standard deviation 200, the average was found to be 50. A 95% confidence interval for the true mean is c.) A.C. Neilsen reported that children between the ages...
In a random sample of five people, the mean driving distance to work was 20.2 miles and the standard deviation was 5.8 miles. Assuming the population is normally distributed and using the t-distribution, a 95% confidence interval for the population mean μ is (13.0, 27.4) (and the margin of error is 7.2). Through research, it has been found that the population standard deviation of driving distances to work is 6.6.Using the standard normal distribution with the appropriate calculations for a...
5) In a simple random sample of 59 electronic components produced by a certain method, the mean lifetime was 1,114 hours. Assume the component lifetimes are normally distributed with population standard deviation 55 hours. What is the upper bound of the 95% confidence interval for the mean lifetime of the components? Round to nearest integer. 6) Efficiency experts study the processes used to manufacture items in order to make them as efficient as possible. One of the steps used to...
6.2.19-T Question Help In a random sample of four microwave ovens, the mean repair cost was $85.00 and the standard deviation was $13.00. Assume the population is normally distributed and use a t-distribution to construct a 99% confidence interval for the population mean μ. What is the margin of error of μ? Interpret the results. The 99% confidence interval for the population mean μ is (DD (Round to two decimal places as needed.) 6.2.21-T Question Help In a random sample...
III 4. The standard deviation of the ages of a random sample of 40 television sets in a neigl forhood 3 years. Find a 95% confidence interval for the standard deviation of the entire population of levisions in this neighborhood. Assume that these ages are randomly distributed.
In a random sample of 11 people, the mean driving distance to work was 25.2 miles and the standard deviation was 7.3 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Identify margin of error Construct a 95% confidence interval for the population mean (___,___)
A simple random sample of 16 observations is derived from a normally distributed population with a known standard deviation of 2.5. [You may find it useful to reference the z table.] a. Is the condition that X− is normally distributed satisfied? Yes No b. Compute the margin of error with 95% confidence. (Round intermediate calculations to at least 4 decimal places. Round "z" value to 3 decimal places and final answer to 2 decimal places.) c. Compute the margin of...
= Question Help For a random sample of 400 students, the mean cost for textbooks during the first semester of college was found to be $374.75, and the sample standard deviation was $30.81. Assuming that the population is normally distributed, find the margin of error of a 95% confidence interval for the population mean The margin of error for a 98% confidence interval is (Round to two decimal places as needed.) I
In a random sample of six mobile devices, the mean repair cost was $80.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results. The 95% confidence interval for the population mean mu is
A simple random sample of 24 observations is derived from a normally distributed population with a known standard deviation of 7.8. [You may find it useful to reference the z table.] a. Is the condition that X−X− is normally distributed satisfied? Yes No b. Compute the margin of error with 99% confidence. (Round intermediate calculations to at least 4 decimal places. Round "z" value to 3 decimal places and final answer to 2 decimal places.) Margin error: ? c. Compute...