Question

For each of the following reactions, 12.0 g of each reactant is present initially.

Determine the limiting reactant.
CS2(g)+3O2(g)→CO2(g)+2SO2(g)

Express your answer as a chemical formula.

O2

Correct

Need help with part F

Part F

Calculate the grams of product in parentheses that would be produced.
(CO2)

Express your answer with the appropriate units.

m(CO2) m(CO2) =

Answer 1

CS2 + 3 O2 ---------------------------> CO2 + 2SO2
no of moles = mass / molar mass

for cs2 = 12 / 76.139 = 0.1576 moles

for o2 = 12 / 32 = 0.375 moles

from the balanced equation

1 mol cs2 ------------------------------> 1 mol co2

0.1576 mol-------------------------------->?

=> 0.1576*1/1 = 0.1576 moles

3 moles o2 --------------------------> 1 mol co2

0.375 moles------------------------> ?

=> 0.375 * 1 / 3 = 0.125 moles

limitting reactant is o2

mass of co2 => 0.125 * 44 = 5.5 grmas of co2        ( mass = moles * molar mass)

answer => 5.5 g of co2