Question

in C++ CS121 Lab 6 March 29, 2019 Write a program that will ask the user to enter 2 integers, with the first less than the second. If the first is not less that the second, display a message. The program will then check all the integers between the 2 numbers (inclusive) to see if they are divisible by 3, 4, 5, and 6, and if so, display a message It will then ask if they want to go again, and if so, repeat the process.

Answer 1

code:-

#include <iostream>

using namespace std;

int main()
{
    int num1,num2;
    char repeater = 't';// to check that user wants to go again or not.
    while(repeater=='t')
    {
    cout<<"Enter two integers and first number should be greater than second "<<endl;
    cin>>num1>>num2;
    char checker = 'f';//to check that user has enter first number greater than second
    while(checker=='f')
    {
        if(num1>num2)
            checker='t';
        else
        {
            cout<<"\nsecond number entered is greater than first number.\nplease enter the which is smaller than "<<num1<<endl;
            cin>>num2;
        }
    }
    int i;//for loop counter
    for(i=num2; i<=num1; i++)
    {
        if(i%3==0)
            cout<<"\n"<<i<<" which is between "<<num1<<" and "<<num2<<" is divisible by 3"<<endl;
        if(i%4==0)
            cout<<"\n"<<i<<" which is between "<<num1<<" and "<<num2<<" is divisible by 4"<<endl;
        if(i%5==0)
            cout<<"\n"<<i<<" which is between "<<num1<<" and "<<num2<<" is divisible by 5"<<endl;
        if(i%6==0)
            cout<<"\n"<<i<<" which is between "<<num1<<" and "<<num2<<" is divisible by 6"<<endl;
    }
    cout<<"\nEnter character t to continue :";
    cin>>repeater;
    if(repeater!='t')
        cout<<"\nThanks for using this program"<<endl;
    }

    return 0;
}

output:-