Let x be the dimension of the part .
A part is defective if x<39.8 and x >40.2
In normal distribution ,
z=x-mean/std dev
Given : mean=39.98 and std dev =0.08
P(x=39.8)=P(z=39.8-39.98/0.08) =P(z=-2.5)=0.012224
P(x=40.2)=P(x=40.2-39.98/0.08)=P(z=2.75)=0.99702
P(x>40.2)=1-P(x=40.2)=1-0.99702=0.00298
Probability that the dimension is not within the dimension =P(x<39.8)+P(x>40.2)
=0.012224+0.00298
=0.015204
=1.52 %
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