The trivalent anion composed of silver(I) and thiosulfate is quantitatively precipitated by hexaminecobalt(III) trichloride. A 25.00 mL portion of photographic fixer, which contains and unknown amount of trivalent silver(I) thiosulfate, was analyzed, and yielded 0.4161 g of the complex product. Calculate the grams of silver contained in one liter of the fixer solution. [Co(NH3)6]3+ + [Ag(S2O3)2]3– → [Co(NH3)6][Ag(S2O3)2] (s)
Given : mass [Co(NH3)6][Ag(S2O3)2] = 0.4161 g
moles [Co(NH3)6][Ag(S2O3)2] = (mass [Co(NH3)6][Ag(S2O3)2]) / (molar mass [Co(NH3)6][Ag(S2O3)2])
moles [Co(NH3)6][Ag(S2O3)2] = (0.4161 g) / (493.24 g/mol)
moles [Co(NH3)6][Ag(S2O3)2] = 8.436 x 10-4 mol
moles silver = moles [Co(NH3)6][Ag(S2O3)2]
moles silver = 8.436 x 10-4 mol
mass silver = (moles silver) * (molar mass silver)
mass silver = (8.436 x 10-4 mol) * (107.868 g/mol)
mass silver = 0.0910 g
This mass of silver is present in 25.00 mL of fixer
For 1 L,
mass silver = 0.0910 g * (1000 mL / 25.00 mL)
mass silver = 0.0910 g * (40)
mass silver = 3.640 g
The trivalent anion composed of silver(I) and thiosulfate is quantitatively precipitated by hexaminecobalt(III) trichloride. A 25.00...