Question

During a circus act, one performer swings upside down hanging from a trapeze while holding another...

During a circus act, one performer swings upside down hanging from a trapeze while holding another performer, also upside-down, by the calves. The legs (femurs) of the lower performer undergo deformation due to the upward force from the upper performer.

If the upward force on the lower performer's legs is 3mg (three times her weight), how much do the bones (the femurs) in her upper legs stretch in meters? You may assume each bone is equivalent to a uniform rod 35 cm long and 1.8 cm in radius and the legs are massless, serving only to transmit the upward force on the torso. Her mass is 62 kg and Young's modulus for tension on bones is 1.6 × 1010 N/m2.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Hope this helps...

Add a comment
Know the answer?
Add Answer to:
During a circus act, one performer swings upside down hanging from a trapeze while holding another...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • During a circus act, one performer swings upside down hanging from a trapeze holding another, also...

    During a circus act, one performer swings upside down hanging from a trapeze holding another, also upside down, performer by the legs. If the upward force on the lower performer is three times her weight, how much does each of the bones (the femurs) in her upper legs stretch (in m)? You may assume each is equivalent to a uniform rod 35.0 cm long and 1.80 cm in radius. Her mass is 51.5 kg. Assume Young's modulus for bone under...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT