An ideal gas has spherical molecules with a diameter of 3x10^-10 m. When the temperature is 20 °C, under how much pressure the mean-free path of molecules is equal to 50 cm?

The values of square root of 2 = 1.414 and Pi = 3.143
Therefore, P = (0.082057 L atm mol-1 K-1 X 293.15 K) / [1.414 X 3.143 X (3 X 10 -8 cm)2 X 6.022 X 1023 mol-1 X 50 cm]
= 24.055 L atm / 12043.34 X 107 cm2 X cm ( all other units cancel outs in numerator and denominator)
=0.001997 X 107 atm ( the unit L = cm3 in numerator cancel outs with denominator )
~ 2.0 X 1010 atm
Answer: The pressure will be 2.0 X 1010 atm
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