Polyprotic acids contain more than one dissociable proton. Each dissociation step has its own acid-dissociation constant, Ka1, Ka2, etc. For example, a diprotic acid H2A reacts as follows:
| H2A(aq)+H2O(l)⇌H3O+(aq)+HA−(aq) |
| Ka1=[H3O+][HA−][H2A] |
| HA−(aq)+H2O(l)⇌H3O+(aq)+A2−(aq) |
| Ka2=[H3O+][A2−][HA−] |
In general, Ka2 = [A2−] for a solution of a weak diprotic acid because [H3O+]≈[HA−].
Many household cleaning products contain oxalic acid, H2C2O4, a diprotic acid with the following dissociation constants: Ka1=5.9×10−2, Ka2=6.4×10−5
Part A) Calculate the equilibrium concentration of H3O+ in a 0.20 M solution of oxalic acid. Answer = 0.083 M
Part B) The question i need help on!
Calculate the equilibrium concentration of C2O42− in a 0.20 M solution of oxalic acid. Express your answer to two significant figures and include the appropriate units.
Polyprotic acids contain more than one dissociable proton. Each dissociation step has its own acid-dissociation constant,...
Determine the concentration of all chemical species found in a solution of 0.20M oxalic acid (H2C2O4) a diprotic acid with Ka1=5.9*10^-2 and Ka2=6.5*10^-5. (Hint: start by writing the two equilibrium that describes the dissociation of the diprotic acid) Determine the pH of the solution. is H3O+ produced in the second equilibrium negligible?
Consider the acid dissociation reactions and for the diprotic acid H2A: H2A(aq) + H2O (l) --><-- HA-(aq) + H3O+(aq) pKa1= 3 H2A(aq) + H2O (l) --><-- A2- (aq) + H3O+(aq) pKa2= 8 Would a salt solution of KHA be acidic, basic or neutral? a) Acidic b) Basic c) Neural
Determine the concentration of H3O+ in a 0.064 M solution of oxalic acid, H2C2O4.H2C2O4(aq)+H2O(l) ⇌ H3O+(aq)+HC2O−4(aq) Ka1=0.054HC2O−4(aq)+H2O(l) ⇌ H3O+(aq)+C2O2−4(aq) Ka2=5.4×10−5
A diprotic acid, H2A, has acid dissociation constants of
Ka1=1.01×10−4 and Ka2=4.08×10−12. Calculate the pH and molar
concentrations of H2A, HA−, and A2−at equilibrium for each of the
solutions.
A diprotic acid, H, A, has acid dissociation constants of Kal = 1.01 x 104 and K22 = 4.08 x 10-12. Calculate the pH and molar concentrations of H, A, HA, and A? at equilibrium for each of the solutions. A 0.176 M solution of H, A. pH= pH = 1...
A diprotic acid, H,A, has acid dissociation constants of Ka1 = 2.09 x 104 and Ka2 = 3.96 x 10-11. Calculate the pH and molar concentrations of H,A, HA-, and A2- at equilibrium for each of the solutions. A 0.183 M solution of H,A pH H,A= A2-1 HA] = A 0.183 M solution of N2HA. HA pH= HA A2- A 0.183 M solution of Na, A H,A ] pH= HA A2-1 M M
A diprotic acid, H,A, has acid dissociation...
Oxalic acid (HOOC-COOH) is a simple diprotic acid. It is used commercially in bleaching straw and leather and removing rust and ink stains. a. Write each dissociation step for the acid including the K values from appendix C. b. What are the equilibrium concentrations of [H2C2O4], [HC2O4- ], and [C2O42- ] in a 0.150M H2C2O4 solution. (Hint: the concentrations of [H2C2O4], [HC2O4- ] are found together and used to find concentration of [C2O42- ].) c. What is the pH of...
A diprotic acid, H2A, has acid dissociation constants of Kai = 3.52 x 10-4 and Ka2 = 2.03 × 10-11 . Calculate the pH and molar concentrations of H2A, HA, and A2- at equilibrium for each of the solutions. A 0.206 M solution of H,A. pH = H2A] HA1 A 0.206 M solution of NaHA pH- [H2A] = [HA-] = A 0.206 M solution of Na,A. pH- [H2A] EA T [A21
A diprotic acid, H,A, has acid dissociation constants of Ka molar concentrations of H,A, HA-, and A2- at equilibrium for each of the solutions 1.42 x 10-4 and Ka2 = 4.07 x 1012. Calculate the pH and = A 0.210 M solution of H,A H2A] = pH HA- A2- М М A 0.210 M solution of NaHA HA pH= М
A diprotic acid, H2A,H2A, has acid dissociation constants of ?a1=4.15×10−4Ka1=4.15×10−4 and ?a2=3.73×10−12.Ka2=3.73×10−12. Calculate the pH and molar concentrations of H2A,H2A, HA−,HA−, and A2−A2− at equilibrium for each of the solutions. A 0.176 M0.176 M solution of H2A.H2A. pH = [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= MM A 0.176 M0.176 M solution of NaHA.NaHA. pH= [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= MM A 0.176 M0.176 M solution of Na2A.Na2A. pH= [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= M
Worksheet 19 Titration of Polyprotic Acids Name: 1. Calculate the sulfite ion [SO3'] concentration in a 0.123 M solution of the weak acid, sulfurous acid (H2SO3). The stepwise dissociation constants of carbonic acid are: Ka1 1.41 x 102 Ka2-6.31 x 108 3. Consider the following dissociation of the triprotic acid, phosphoric acid (HsPOs): Step 1 H3POa + H2O <=> H30+ + H2PO4, Step 2 HP0i + H2O <=> H30+ + HP042- Step 3 HPO42-+ H2O <-> H3O+ + PO43- Kal=7.1...