Attenuation works through the action of ribosomes binding to an mRNA and signaling to RNA polymerase whether it should terminate transcription or not. However, once that decision is made (one way or the other), it would seem wasteful for the leader peptide to continue to be made; after all, the decision has been made, and thus there is no more need for ribosomes to act. Invent a model that would allow the attenuation region to no longer be involved in binding ribosomes and synthesizing leader peptides after the attenuation decision is made. How could you experimentally test your model?
Answer. Attenuation occur because ribosomes synthesized new short leader peptide which bind to mRNA and stop the RNA polymerase for transcription.
If we synthesized artificial complementary short segment of leader sequence and added after hair pin formation it work just like attenuation without addition of any ribosomes to mRNA segment and transcription get stop and their is no need of synthesized premature leader peptide before translation.
Attenuation works through the action of ribosomes binding to an mRNA and signaling to RNA polymerase...
2. When transcribing an mRNA strand, RNA polymerase uses the strand of DNA to match complementary bases with. RNA polymerase always reads this strand in the direction and always builds mRNA in the direction. (1.5 pts) 3. (0.5 pt) What is the significance of the +1 site in regards to transcription of mRNA? t) When translating an mRNA sequence, where does the ribosome always begin? 5. (0.5 pt) When translating an mRNA sequence, what signals the ribosome to end translation?...
13. Why are ribonucleoside triphosphates the monomers required for RNA synthesis rather than ribonucleoside monophosphates? A. Only ribonucleoside triphosphates contain the sugar ribose. B. Ribonucleoside triphosphates have low potential energy, making the polymerization reaction endergonic. C. Ribonucleoside triphosphates have high potential energy, making the polymerization reaction exergonic. D. Ribonucleoside monophosphates cannot form complementary base pairs with the DNA template. E. Ribonucleoside triphosphates are not used, rather all use deoxyriboside triphosphates. 14. How is a mutation in a bacterial cell that...