When fluorite (CaF2; see photo) is pulverized and shaken in water at 18oC, 10.0 mL of the solution contains 1.5 x 10-4 g of solute. Find the Ksp of CaF2 at 18oC.
Given mass = 1.5 x 10-4 g of solute
molarity = (weight / gram molecular mass of CaF2) x (10 /1000)
= (1.5 x 10-4 / 78.1) x 10-2 M
= 0.0192 x 10-6 M
CaF2 <===> Ca+2 + 2F-
solulibilty product constant Ksp = [Ca+2] [F-]2
= [s] [2s]2
= 4s3
= 4 x (0.0192 x 10-6 M)3
= 2.83 x 10-11
When fluorite (CaF2; see photo) is pulverized and shaken in water at 18oC, 10.0 mL of...
Fluorite, CaF2, is a slightly soluble salt in water. In a saturated solution, the concentration of [Ca2+] = 2.5 x 10^-4 and [F-] = 4.30 x 10^-4 a. write the dissolution equation for fluorite. b. Write Ksp expression for the dissolution of fluorite. c. Calculate the Ksp.
please show work
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Question 13 which of the following is a strong electrolyte
(see photo)
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