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The following code is used to set (1) and clear (0) certain bits of a one...

The following code is used to set (1) and clear (0) certain bits of a one byte variable. The initial state of all bits is unknown ('x'). After both of the following commands are executed in the order shown , determine which bits are known to be 1. A &= ~0x03; A |= ~0x30; Note: A |= 0xFB is the same command as A = A | 0xFB

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Answer #1

The first command is

This is equivalent to

First lets find . This is the bitwise complement of 0x03

So

Now & is bitwise AND. So

So after the command , the content of A will be

The second command is

This is equivalent to

We already showed

Now | is bitwise OR. So

So after the second command, the content of A will be

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